## Alligation

Question 1 |

Rs. 18.50 | |

Rs. 19.50 | |

Rs. 19 | |

Rs. 18 |

Question 2 |

10 | |

20 | |

21 | |

25 |

Question 3 |

Rs. 175.50 | |

Rs. 170 | |

Rs. 180 | |

Rs. 169.50 |

So, their average price

So, the mixture is formed by mixing two varieties, one at Rs. 130.50 per kg and the other at say, Rs. *x* per kg in the ratio 2 : 2, *i.e.*, 1 : 1. We have to find *x*.

Question 4 |

10% | |

16% | |

19% | |

21% |

Now, given ratio of Ram and Shayam's weight = 4:5

Hence, (x-15)/(15-10) = 4/5

Or, x = 19%

Question 5 |

110 | |

100 | |

90 | |

120 |

Heads Count = 200.

Legs count = 580.

Average Legs count for per head = 580/200 = 29/10.

Rabbits : Pigeons = (9/10) : (11/10)= 9 : 11.

Number of Pigeons = (200 *11)/20 = 110.

Question 6 |

3:5 | |

2:5 | |

5:3 | |

5:2 |

CP of Second tea = Rs. 150 per kg.

Mixture is to be sold in Rs. 194.40 per kg, which has included 20% profit. So,

SP of Mixture = Rs. 194.40 per kg.

Let the CP of Mixture be Rs. X per kg. Therefore,

X + 20% of X = SP

6X /5 = 194.40

6X = 194.40 *5

X = Rs. 162 per kg.

Let N kg of first tea and M kg of second tea to be added.

Now, Using Alligation,

We get,

N/M = 12/30

N : M = 2 : 5.

Question 7 |

68 | |

22 | |

44 | |

136 |

Hence,the number of Deers = (180*88)/360 = 44.

Question 8 |

3 L | |

5 L | |

9 L | |

4 L |

We use formula for it where

n = no. of time process of out going repeated.

y = Out going milk in process.

x = Volume of original solution.

F = Final milk left in mixture.

Final quantity of water,

= x[1-(y/x)]^{n}

= x[1-(3/x)]^{3}

F/x = x[1-(3/x)]^{3}

27/1728 = x[1-(3/x)]^{3}

Or, x = 4 L.

Question 9 |

3 : 4 | |

2 : 3 | |

4 : 5 | |

1 : 3 |

Question 10 |

Rs. 408 | |

Rs. 267.5 | |

Rs. 412.6 | |

None of these |

Or, x = (680*3)/5

Hence, x = Rs. 408.