# YOU CAN DOWNLOAD 200+ SUBJECTS PDF BOOK FOR COMPETITIVE EXAMINATIONS CLICK HERE TO DOWNLOAD ## Comb Sort Multiple choice Questions and Answers (MCQs)

 Question 1 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Comb sort is an improved version of .....
 A Selection sort B Bubble sort C Insertion sort D Merge sort
Question 1 Explanation:
Comb sort compares two elements at a variable gap from each other in each iteration unlike bubble sort where the gap remains 1. This reduces the average time complexity of comb sort.

 Question 2 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The gap between two elements being compared shrinks by a factor of ..... after every iteration.
 A 1.1 B 1.2 C 1.3 D 1.4
Question 2 Explanation:
It has been found experimentally that the gap between the two elements should shrink by a factor of 1.3 after each iteration for the most efficient sorting.

 Question 3 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The initial gap between two elements being compared .....
 A is equal to number of elements in the array B is equal to 1.3 C depends on the number of iterations D depends on the compiler being used
Question 3 Explanation:
Initial gap is taken to be equal to the number of elements in the array and shrinks by a factor of 1.3 in each iteration, initial gap is independent of the number of iterations and compiler being used.

 Question 4 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What is the worst case time complexity of comb sort?
 A O(n2) B O(n log n) C O(n) D O(n2/2a) (a=number of increment)
Question 4 Explanation:
Worst case complexity is observed when the input array is reverse sorted. This is same as the worst case complexity of bubble sort.

 Question 5 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The gap value after 3 iterations in an array with 6 elements will be .....
 A 4 B 3 C 2 D 1
Question 5 Explanation:
Initially the gap value will be 6. For the first iteration, it will be 6/1.3=4 then 4/1.3=3 for second iteration and 3/1.3=2 for the third iteration.

There are 5 questions to complete.