Computer networking MCQ

1171. If the bandwidth of a signal is 5 KHz and the lowest frequency is 52 KHz, what is the highest frequency?

Correct Answer: Correct answer is: (D) 57 KHz.

Exam Relevance: Physics Exams, Electronics Exams, Signal Processing Exams

Difficulty: Easy

Concept notes: The bandwidth of a signal is the difference between the highest and lowest frequencies of the signal.

Common Mistakes: Students may confuse the bandwidth with the highest frequency directly, without considering the lowest frequency.

Explanations: The bandwidth of the signal is given as 5 KHz. The lowest frequency is 52 KHz. To find the highest frequency, we add the bandwidth to the lowest frequency: 52 KHz + 5 KHz = 57 KHz.

Option Analysis:

Option A: 5 KHz is the bandwidth, not the highest frequency.
Option B: 10 KHz is not related to the given information.
Option C: 47 KHz is below the lowest frequency, which is not possible.
Option D: 57 KHz is the correct highest frequency, calculated by adding the bandwidth to the lowest frequency.

1172. When a mobile phone is called, telephone central office sends number to the

Correct Answer: Correct answer is: (B) MCS.

Exam Relevance: GATE, GRE, GMAT, Professional Certification Exams

Difficulty: Moderate

Concept notes: MCS stands for Mobile Switching Center, which is responsible for routing calls to the correct mobile station.

Common Mistakes: Students may confuse MCS with other acronyms like FDMA (Frequency Division Multiple Access) or MSs (Mobile Stations).

Explanations: When a mobile phone is called, the telephone central office sends the number to the Mobile Switching Center (MCS). The MCS is a critical component of the mobile network infrastructure that handles the routing of calls to the appropriate mobile station. It acts as an intermediary between the telephone central office and the mobile stations, ensuring that the call is directed to the correct recipient.

Option Analysis:

Option A: FDMA (Frequency Division Multiple Access) is a method of dividing the frequency spectrum into separate channels, not a component that handles call routing.
Option B: MCS (Mobile Switching Center) is the correct component responsible for routing calls to the correct mobile station.
Option C: MSs (Mobile Stations) are the devices (phones) that receive the calls, not the component that routes them.
Option D: MSD (Mobile Switching Device) is not a standard term in mobile network terminology.

Mnemonic: MCS: Mobile Calls Switch

1173. Processing which is carried out by use of remote terminal processors is called

Correct Answer: Correct answer is: (A) Teleprocessing.

Exam Relevance: Computer Science Exams, Information Technology Exams, Networking Exams

Difficulty: Easy

Concept notes: Teleprocessing refers to the processing of data using remote terminal processors, which allows users to access and interact with a central computer system from a distance.

Common Mistakes: Students may confuse teleprocessing with digital processing, which involves the manipulation of digital data, or logical processing, which involves the application of logical operations.

Explanations: Teleprocessing is the correct term for processing carried out by remote terminal processors. This method allows users to access and interact with a central computer system from a remote location, making it distinct from other forms of processing such as digital or logical processing.

Option Analysis:

Option A: Teleprocessing is the correct term for processing carried out by remote terminal processors.
Option B: Digital processing involves the manipulation of digital data, not remote terminal processing.
Option C: Logical processing involves the application of logical operations, not remote terminal processing.
Option D: Manual processing involves human intervention, not remote terminal processing.

1174. In which OSI layer does routing occur?

Correct Answer: Correct answer is: (A) Network.

Exam Relevance: CCNA, CISSP, CompTIA Network+

Difficulty: Easy

Concept notes: Routing occurs in the Network layer of the OSI model, which is responsible for determining the best path for data to travel across networks.

Common Mistakes: Students often confuse the Network layer with the Data Link layer, which is responsible for physical addressing and error detection.

Explanations: Routing involves determining the best path for data to travel from a source to a destination across multiple networks. This function is performed at the Network layer (Layer 3) of the OSI model. The Network layer uses logical addresses (IP addresses) to route packets to their destination. The Data Link layer (Layer 2) and Physical layer (Layer 1) are responsible for physical addressing and transmission, while the Transport layer (Layer 4) handles end-to-end communication.

Option Analysis:

Option A: Correct. Routing occurs in the Network layer.
Option B: Incorrect. The Data Link layer is responsible for physical addressing and error detection, not routing.
Option C: Incorrect. The Physical layer is responsible for the physical transmission of data, not routing.
Option D: Incorrect. The Transport layer is responsible for end-to-end communication, not routing.

1175. . The protocol that maps IP addresses to a Media Access Control (MAC) address is:

Correct Answer: Correct answer is: (C) Address Resolution Protocol (ARP).

Exam Relevance: CCNA, CISSP, CompTIA Network+

Difficulty: Easy

Concept notes: The Address Resolution Protocol (ARP) is used to map IP addresses to MAC addresses, which is essential for communication within a local network.

Common Mistakes: Students often confuse ARP with other protocols like DHCP, which is used for assigning IP addresses to devices, or IMAP, which is used for accessing email.

Explanations: ARP is the protocol that maps IP addresses to MAC addresses. When a device needs to communicate with another device on the same network, it uses ARP to find the MAC address associated with the IP address of the destination device. This mapping is crucial for the lower layers of the network stack to ensure packets are delivered to the correct physical device.

Option Analysis:

Option A: IMAP is used for accessing email, not for mapping IP addresses to MAC addresses.
Option B: DHCP is used for assigning IP addresses to devices, not for mapping IP addresses to MAC addresses.
Option C: ARP is the correct protocol for mapping IP addresses to MAC addresses.
Option D: UDP is a transport layer protocol used for sending datagrams, not for mapping IP addresses to MAC addresses.

Mnemonic: ARP: Always Resolves Protocol

1176. A link from a hypertext document to another location, activated by clicking on a highlighted word or image.

Correct Answer: Correct answer is: (C) Hyperlink.

Exam Relevance: SAT, ACT, AP Computer Science Principles

Difficulty: Easy

Concept notes: A hyperlink is a reference to a document or other resource on the internet, which can be activated by clicking on a highlighted word or image.

Common Mistakes: Students may confuse hyperlinks with hyper text, which refers to the text that contains hyperlinks, rather than the link itself.

Explanations: A hyperlink is a clickable element in a hypertext document that allows navigation to another location, such as a different webpage or a specific section within the same document. When a user clicks on a hyperlink, they are directed to the linked content. This makes hyperlinks essential for navigating the web and connecting different pieces of information.

Option Analysis:

Option A: Hyper Text refers to text that contains hyperlinks, not the link itself.
Option B: Hyper Image is not a standard term in web technology.
Option C: Hyperlink is the correct term for a clickable reference to another location.
Option D: Hyphen is a punctuation mark and not related to web navigation.

1177. Difference in delay of signal may create a difference in

Correct Answer: Correct answer is: (A) Phase.

Exam Relevance: EEG, ECE, GATE, GRE Physics

Difficulty: Moderate

Concept notes: The phase of a signal is a measure of its position in its cycle at a given time. A delay in the signal means that the signal is shifted in time, which directly affects its phase.

Common Mistakes: Students often confuse phase with frequency, thinking that a delay would change the frequency of the signal. However, frequency is the number of cycles per unit time and is not affected by a time delay.

Explanations: A delay in a signal causes a shift in its time domain, which translates to a phase shift in the signal. The phase of a signal is a measure of its position in its cycle at a given time. Therefore, a delay in the signal means that the signal is shifted in time, which directly affects its phase. Frequency, period, and decibel are not affected by a time delay.

Option Analysis:

Option A: Correct. A delay in the signal causes a phase shift.
Option B: Incorrect. Frequency is the number of cycles per unit time and is not affected by a time delay.
Option C: Incorrect. Period is the time for one complete cycle and is not affected by a time delay.
Option D: Incorrect. Decibel is a measure of signal strength and is not affected by a time delay.

Mnemonic: Delay = Phase Shift

1178. In gigabit Ethernet three or more stations are connected by

Correct Answer: Correct answer is: (C) Star Topology.

Exam Relevance: CCNA, Network+, CompTIA Network+

Difficulty: Moderate

Concept notes: In gigabit Ethernet, the star topology is commonly used to connect multiple stations to a central hub or switch.

Common Mistakes: Students may confuse the star topology with the bus topology, which is less common in modern Ethernet networks.

Explanations: In a star topology, each station is connected directly to a central hub or switch. This allows for efficient data transmission and easy troubleshooting. The central hub or switch acts as a central point for all data transmission, ensuring that data packets are directed to the correct destination. This topology is particularly suitable for gigabit Ethernet because it supports high-speed data transfer and can handle multiple simultaneous connections without significant degradation in performance.

Option Analysis:

Option A: Ring Topology is not typically used in gigabit Ethernet because it can introduce latency and is less scalable.
Option B: Bus Topology is less common in modern Ethernet networks due to its limitations in handling high-speed data transfer and scalability.
Option C: Star Topology is the correct choice as it is widely used in gigabit Ethernet for its efficiency and scalability.
Option D: Mesh Topology is more complex and typically used in scenarios requiring high redundancy, not common in standard gigabit Ethernet setups.

Mnemonic: STAR: Single Trunk And Radiating

1179. ..... uses two pairs of twisted-pair cable.

Correct Answer: Correct answer is: (A) 100Base-TX.

Exam Relevance: CCNA, CompTIA Network+, CIW Network Specialist

Difficulty: Moderate

Concept notes: 100Base-TX is a type of Ethernet that uses two pairs of twisted-pair cables for data transmission.

Common Mistakes: Students may confuse 100Base-TX with 100Base-FX, which uses fiber optic cables instead of twisted-pair cables.

Explanations: 100Base-TX is a Fast Ethernet standard that operates at 100 Mbps and uses two pairs of Category 5 (or higher) twisted-pair cables. One pair is used for transmitting data, and the other pair is used for receiving data. This configuration allows for full-duplex communication, where data can be sent and received simultaneously. The use of twisted-pair cables makes 100Base-TX cost-effective and easy to install in a typical office or home environment.

Option Analysis:

Option A: 100Base-TX uses two pairs of twisted-pair cable, which is correct.
Option B: 100Base-FX uses two strands of fiber optic cable, not twisted-pair cable.
Option C: 100Base-T4 uses four pairs of twisted-pair cable, not two pairs.
Option D: This option is incorrect as 100Base-TX is the correct answer.

Mnemonic: TX for Twisted-pair, Two pairs.

1180. Term that refers to phase continues through boundary of two signal elements is

Correct Answer: Correct answer is: (B) Coherent BFSK.

Exam Relevance: GATE, ECE exams, IEEE exams

Difficulty: Moderate

Concept notes: Coherent BFSK (Binary Frequency Shift Keying) refers to a modulation technique where the phase of the carrier signal is continuous across the boundaries of signal elements. This ensures that the phase does not abruptly change, maintaining coherence.

Common Mistakes: Students often confuse coherent and non-coherent BFSK. Non-coherent BFSK does not maintain phase continuity across signal boundaries, leading to phase discontinuities.

Explanations: In coherent BFSK, the phase of the carrier signal remains continuous through the boundaries of two signal elements. This continuity ensures that the phase does not abruptly change, which is a key characteristic of coherent BFSK. Non-coherent BFSK, on the other hand, does not maintain this phase continuity, leading to phase discontinuities at the boundaries of signal elements.

Option Analysis:

Option A: Non-coherent BFSK does not maintain phase continuity across signal boundaries, leading to phase discontinuities.
Option B: Coherent BFSK maintains phase continuity across signal boundaries, ensuring the phase does not abruptly change.
Option C: Binary ASK (Amplitude Shift Keying) modulates the amplitude of the carrier signal, not the phase, and does not inherently ensure phase continuity.
Option D: Multilevel ASK modulates the amplitude of the carrier signal to represent multiple levels, but it does not inherently ensure phase continuity.

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Computer networking MCQ - Set 118

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