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## Hashing Functions Multiple choice Questions and Answers (MCQs)

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Question 1 [CLICK ON ANY CHOICE TO KNOW MCQ multiple objective type questions RIGHT ANSWER] |

Which scheme uses a randomization approach?

hashing by division | |

hashing by multiplication | |

universal hashing | |

open addressing |

Question 1 Explanation:

Universal hashing scheme uses a randomization approach whereas hashing by division and hashing by multiplication are heuristic in nature.

Question 2 [CLICK ON ANY CHOICE TO KNOW MCQ multiple objective type questions RIGHT ANSWER] |

Which hash function satisfies the condition of simple uniform hashing?

h(k) = lowerbound(km) | |

h(k)= upperbound(mk) | |

h(k)= lowerbound(k) | |

h(k)= upperbound(k) |

Question 2 Explanation:

If the keys are known to be random real numbers k independently and uniformly distributed in the range 0<=k<=1, the hash function which satisfies the condition of simple uniform hashing is

h(k)= lowerbound(km).

Question 3 [CLICK ON ANY CHOICE TO KNOW MCQ multiple objective type questions RIGHT ANSWER] |

A good hash approach is to derive the hash value that is expected to be dependent of any patterns that might exist in the data.

True | |

False |

Question 3 Explanation:

A hash value is expected to be unrelated or independent of any patterns in the distribution of keys.

Question 4 [CLICK ON ANY CHOICE TO KNOW MCQ multiple objective type questions RIGHT ANSWER] |

Interpret the given character string as an integer expressed in suitable radix notation.

Character string = pt

14963 | |

14392 | |

12784 | |

14452 |

Question 4 Explanation:

The given character string can be interpreted as (112, 116) (Ascii values) then expressed as a radix-128 integer, hence the value is 112*128 + 116 = 14452.

Question 5 [CLICK ON ANY CHOICE TO KNOW MCQ multiple objective type questions RIGHT ANSWER] |

What is the hash function used in the division method?

h(k) = k/m | |

h(k) = k mod m | |

h(k) = m/k | |

h(k) = m mod k |

Question 5 Explanation:

In division method for creating hash functions, k keys are mapped into one of m slots by taking the reminder of k divided by m.

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