puzzles quantitative aptitude test

Online aptitude test questions and answers for company exam

Question 141
REYKJAVIK 4032737411 WORCESTERSH 384427524240 MISSISSIPPI 728388993164 CZECHOSLOVA?
A
5.41E+11
B
5.41E+11
C
5.41E+11
D
540861235368
Question 141 Explanation: 
Answer : 540861235368

Each alphabet value is coded as below
A= 26, B=25, C=24, D=23, .....Z=1

The final code is generated as = Multiply value of all alphabets + Add Values of all alphabets

For CZECHOSLOVA we have = (24*1*22*24*19*12*8*15*12*5*26) + (24+1+22+24+19+12+8+15+12+5+26) = 540861235368







Question 142
12 labours construct 120 toys in 8 days working 8 hours per day. If two of them leave the work, then how many days are required to do the same work with a working of 6 hours per day.
A
11.8
B
14
C
12.8
D
10.8
Question 142 Explanation: 
Labour - Toy -- Day --------- Hour
12 ----- 120 -- 8 ------------ 8
1 ------ 120 -- 8*12 --------- 8
1 ------ 120 -- 8*12*8 ------- 1
10 ----- 120 -- 8*12*8/10 ---- 1
10 ----- 120 -- 8*12*8*/10*6 - 6
10 ----- 120 -- 12.8 --------- 6

Question 143
A tank can be filled by a tap A in 10 hours, whereas it can be emptied by tap B and tap C in 6 hours and 12 hours one by one. If all the 3 taps work together, then total time taken for making a fully filled tank empty will be (in hours)
A
5
B
3
C
6.25
D
6.67
Question 143 Explanation: 
total tank filled by tap A in 1 hour = 1/10 part
similarly water drained by tap B in 1 hour = 1/6 part
and by tap C = 1/12 part
so total drained water in 1 hour = 1/6 + 1/12 - 1/10 = 3/20
so total time taken = 20/3 hours






Question 144
If (1/(x+2))+(1/(x+6))=(1/(x+3))+(1/(x+5)) Value of x is
A
-7
B
-4
C
No Soluction
D
-8
Question 144 Explanation: 
Solve
(2x+8)/(x^2+8x+12)=(2x+8)/(x^2+8x+15)
(2x+8)(x^2+8x+15)=(2x+8)(x^2+8x+12)
(2x+8)(x^2+8x+15)-(2x+8)(x^2+8x+12)=0
common (2x+8)
then solve
x=-4
Question 145
Rizwan buys an old scooter for Rs. 26750 and spends Rs. 2175 on its repairs. If he sells the scooter for Rs. 34600, his gain percent is:
A
17.48%
B
19.85%
C
18.06%
D
19.62 %
Question 145 Explanation: 
Cost Price (C.P.) = Rs. (26750 + 2175) = Rs. 28925

Selling Price (S.P.) = Rs. 34600

Gain = (S.P.) - (C.P.) = Rs.(34600 - 28925) = Rs. 5675

Gain % = (5675/28925)*100 = 19.619 = ~19.62 %






Question 146
What are the odds in favour of throwing atleast 7 in a single throw of two dice.
A
2/5
B
5/7
C
5/2
D
7/5
Question 146 Explanation: 
Total number of possible outcomes = 36 (solve)
Let E be the event "Sum of the numbers on the two dice is atleast 7
therefore
E = (1, 6)(2, 5)(3, 4)(4, 3)(5, 2)(6, 1)(2, 6)(3, 5)(4, 4)(5, 3)(6, 2)(3, 6)(4, 5)(5, 4)(6, 3)(4, 6)(5, 5)(6, 4)(5, 6)(6, 5)(6, 6)
n(E)=21, n (not E) = 36-21=15
P(E)=21/36 and P(not E) = 15/36
Odd is favour of the event E = P(E):p(not E)
(21/36):(15/36) = 7:5
7/5
Question 147
The true discount on a bill due 10 months hence at 6% per annum is Rs.26.25. Find the amount of the bill.
A
Rs. 551.25
B
Rs. 750.25
C
Rs. 855.5
D
Rs. 945.5
Question 147 Explanation: 
S.I. on Rs.100 for 10 months at 6% per annum
= Rs.(1000 * 10/12 * 6/100) = Rs.5
=> Amount = Rs.(100+5) = Rs.105
So, T.D. = Rs.(105-100) = Rs.5
If T.D. is Rs.5, sum due = Rs.105
If T.D. is Rs.26.25, sum due = Rs.(105/5 * 26.25) = Rs.551.25






Question 148
If 1+2+3 = 24 7+2+8 = 216 5+8+10 = 594 then 6+7+8 =
A
792
B
432
C
504
D
864
Question 148 Explanation: 
In this question
1+2+3 = 2*3*4 = 24 (add 1 to every digit and multiply all of them)
7+2+8 = 8*3*9 = 216
5+8+10 = 6*9*11 = 594
Similarly
6+7+8 = 7*8*9 = 504

Question 149
If in coded language MOHAN = 24 SALIM = 22 SURESH = 63 Then YASHAR =?
A
32
B
29
C
54
D
30
Question 149 Explanation: 
A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)
MOHAN = (M+O+H+A+N)-(M+N)
MOHAN = (13+15+8+1+14)-(13+14) = 51-27 = 24
SALIM = (19+1+12+9+13)-(19+13) = 54-32 = 22
SURESH = (19+21+18+5+19+8)-(19+8) = 90-27 = 63
Similarly
YASHAR = (25+1+19+8+1+18)-(25+18) = 72-43 = 29






Question 150
A man walks up a mountain at the rate of 2 km an hour and down by a way 6 km longer at the rate of 7/2 km an hour. He is out eight hours altogether. How far has he walked?
A
43 km
B
22 km
C
32 km
D
29 km
Question 150 Explanation: 
Let the way up be x km
Time taken to climb up = x/2 hours.
The way down = (x+6)km
Time taken to climb down =(x+6)/(7/2)= 2(x+6)/7
Therefore the total time of the journey = (x/2)+{2(x+6)/7}=8
solve x = 8
Total distance = x+x+6 = 22km.
There are 150 questions to complete.

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