## Online aptitude test questions and answers for company exam

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Question 191 |

, X y and z are integers such that y+z<8, x>0, y>0, z>0. How many pairs (, Xy) are possible.

64 | |

1380 | |

256 | |

infinite |

Question 191 Explanation:

You can take any value in the place of x

Question 192 |

Find Rank of the word SHIVRATRI in the dictionary of words formed by the letters of the word SHIVRATRI

62230 | |

62219 | |

62250 | |

62240 |

Question 192 Explanation:

SHIVRATRI => AHIIRRSTV

Arranging letters in alphabetical order: AHIIRRSTV => I and R are repeated (2 Is & 2 Rs)

Words starting with Alphabet A = 8!/(2!*2!) = 10080

Words starting with Alphabet H = 8!/(2!*2!) = 10080

Words starting with Alphabet I = 8!/2! = 20160

Words starting with Alphabet R = 8!/2! = 20160

Words starting with Alphabet SA = 7!/(2!*2!) = 1260

Words starting with Alphabet SHA = 6!/(2!*2!) = 180

Words starting with Alphabet SHIA = 5!/2! = 60

Words starting with Alphabet SHII = 5!/2! = 60

Words starting with Alphabet SHIR = 5! = 120

Words starting with Alphabet SHIT = 5!/2! = 60

Words starting with Alphabet SHIVA = 4!/2! =12

Words starting with Alphabet SHIVI = 4!/2! = 12

Words starting with Alphabet SHIVRAI = 2! = 2

Words starting with Alphabet SHIVRAR = 2! = 2

Words starting with Alphabet SHIVRATI = 1 = 1

And next word is SHIVRATRI so +1 for final word

Sum of all words => 2*10080 + 2*20160 + 1260 + 180+ 3*60 + 120 + 2*12 + 2*2 + 1 + 1 =62250

Arranging letters in alphabetical order: AHIIRRSTV => I and R are repeated (2 Is & 2 Rs)

Words starting with Alphabet A = 8!/(2!*2!) = 10080

Words starting with Alphabet H = 8!/(2!*2!) = 10080

Words starting with Alphabet I = 8!/2! = 20160

Words starting with Alphabet R = 8!/2! = 20160

Words starting with Alphabet SA = 7!/(2!*2!) = 1260

Words starting with Alphabet SHA = 6!/(2!*2!) = 180

Words starting with Alphabet SHIA = 5!/2! = 60

Words starting with Alphabet SHII = 5!/2! = 60

Words starting with Alphabet SHIR = 5! = 120

Words starting with Alphabet SHIT = 5!/2! = 60

Words starting with Alphabet SHIVA = 4!/2! =12

Words starting with Alphabet SHIVI = 4!/2! = 12

Words starting with Alphabet SHIVRAI = 2! = 2

Words starting with Alphabet SHIVRAR = 2! = 2

Words starting with Alphabet SHIVRATI = 1 = 1

And next word is SHIVRATRI so +1 for final word

Sum of all words => 2*10080 + 2*20160 + 1260 + 180+ 3*60 + 120 + 2*12 + 2*2 + 1 + 1 =62250

Question 193 |

If Rs.516 are divided among Suresh, Mohan, Shyam so that Suresh receives 25% more than Mohan and Mohan receives 25% less than Shyam, then Shyam's shares is

Rs.196 | |

Rs.168 | |

Rs.192 | |

Rs.144 |

Question 193 Explanation:

Suppose Shyam gets Rs.100 then Mohan gets Rs.75

Suresh gets = 12% of Rs.175) = 375/4

Suresh:Mohan:Shyam = 375/4 : 75 : 100

=375 : 300 : 400

= 15:12:16

Therefore Shyam share = 516*16/43 = Rs. 192 (solve)

Suresh gets = 12% of Rs.175) = 375/4

Suresh:Mohan:Shyam = 375/4 : 75 : 100

=375 : 300 : 400

= 15:12:16

Therefore Shyam share = 516*16/43 = Rs. 192 (solve)

Question 194 |

Some names code are give below ANAND = 4 DEEP = 16 BHUWNESH = 8 then HANSHU =?

15 2 20 | |

12 | |

21 | |

13 |

Question 194 Explanation:

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)

Codes are offered on the basis of positions of last alphabet used in the name

HANSHU = 21

Codes are offered on the basis of positions of last alphabet used in the name

HANSHU = 21

Question 195 |

What is the next number of the following sequence 90, 110, 132, 156, .....

182 | |

342 | |

153 | |

380 |

Question 195 Explanation:

10^2-10 = 90

11^2-11 = 110

12^2-12 = 132

13^2-13 = 156

same

14^2-14 = 182

11^2-11 = 110

12^2-12 = 132

13^2-13 = 156

same

14^2-14 = 182

Question 196 |

Total cost of 2 rubbers and 3 pencils is greater than 20 rupee whereas total cost of 3 rubbers and 2 pencils is less than 24 rupee. If cost of pencil is less then 7 rupee then for what prize of rubber and pencil total cost of 4 rubbers and 5 pencils is minimum

4, 4 | |

2, 5 | |

3, 4 | |

3, 5 |

Question 196 Explanation:

2x+3y > 20

3x+2y < 24

y < 7

We have to find a condition such that 4x+5y is minimum

3x+2y < 24

y < 7

We have to find a condition such that 4x+5y is minimum

Question 197 |

Total volume of a cylindrical tank (in litres), whose internal radius is 10 feet and height is 20 feet is (Given that 1 inch = 2.54 cm, 1000 cm3 = 1 litre and volume of a cylinder = 22 * (radius) 2 * height / 7)

210324 | |

177991 | |

187654 | |

156789 |

Question 197 Explanation:

Volume of a cylinder = 22 * (radius) 2 * height / 7

On taking all the values, we get V = 177991.61 litres

On taking all the values, we get V = 177991.61 litres

Question 198 |

10 percent of 30 plus 30 percent of 10 =?

26 | |

10 | |

8 | |

6 |

Question 198 Explanation:

10% of 30 =3

30% of 10 = 3

6

30% of 10 = 3

6

Question 199 |

Two equal amounts of money are deposited in two banks, each at 15% per annum, for 7/2 years and 5 years. If he difference between their interest is Rs.288, each sum is

1620 | |

1460 | |

1280 | |

640 |

Question 199 Explanation:

Let the sum be x. Then,

(x*5*15)/100 - x*15 * 7/2 * 1/100 = 288

x = 1280

(x*5*15)/100 - x*15 * 7/2 * 1/100 = 288

x = 1280

Question 200 |

If 2.0178 = 107 3.1980 = 681 4.6212 = 1568 5.2120 = 434 Then 6.1074 =

1240 | |

1475 | |

197 | |

99 |

Question 200 Explanation:

Here 2.0178 = 0178/2 + (2+0+1+7+8) = 89 + 18 = 107

Similarly for others

Similarly for others

There are 200 questions to complete.