# puzzles quantitative aptitude test

## Online aptitude test questions and answers for company exam

 Question 191
, X y and z are integers such that y+z<8, x>0, y>0, z>0. How many pairs (, Xy) are possible.
 A 64 B 1380 C 256 D infinite
Question 191 Explanation:
You can take any value in the place of x

 Question 192
Find Rank of the word SHIVRATRI in the dictionary of words formed by the letters of the word SHIVRATRI
 A 62230 B 62219 C 62250 D 62240
Question 192 Explanation:
SHIVRATRI => AHIIRRSTV
Arranging letters in alphabetical order: AHIIRRSTV => I and R are repeated (2 Is & 2 Rs)
Words starting with Alphabet A = 8!/(2!*2!) = 10080
Words starting with Alphabet H = 8!/(2!*2!) = 10080
Words starting with Alphabet I = 8!/2! = 20160
Words starting with Alphabet R = 8!/2! = 20160
Words starting with Alphabet SA = 7!/(2!*2!) = 1260
Words starting with Alphabet SHA = 6!/(2!*2!) = 180
Words starting with Alphabet SHIA = 5!/2! = 60
Words starting with Alphabet SHII = 5!/2! = 60
Words starting with Alphabet SHIR = 5! = 120
Words starting with Alphabet SHIT = 5!/2! = 60
Words starting with Alphabet SHIVA = 4!/2! =12
Words starting with Alphabet SHIVI = 4!/2! = 12
Words starting with Alphabet SHIVRAI = 2! = 2
Words starting with Alphabet SHIVRAR = 2! = 2
Words starting with Alphabet SHIVRATI = 1 = 1
And next word is SHIVRATRI so +1 for final word
Sum of all words => 2*10080 + 2*20160 + 1260 + 180+ 3*60 + 120 + 2*12 + 2*2 + 1 + 1 =62250

 Question 193
If Rs.516 are divided among Suresh, Mohan, Shyam so that Suresh receives 25% more than Mohan and Mohan receives 25% less than Shyam, then Shyam's shares is
 A Rs.196 B Rs.168 C Rs.192 D Rs.144
Question 193 Explanation:
Suppose Shyam gets Rs.100 then Mohan gets Rs.75
Suresh gets = 12% of Rs.175) = 375/4
Suresh:Mohan:Shyam = 375/4 : 75 : 100
=375 : 300 : 400
= 15:12:16
Therefore Shyam share = 516*16/43 = Rs. 192 (solve)

 Question 194
Some names code are give below ANAND = 4 DEEP = 16 BHUWNESH = 8 then HANSHU =?
 A 15 2 20 B 12 C 21 D 13
Question 194 Explanation:
A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25), Z(26)

Codes are offered on the basis of positions of last alphabet used in the name

HANSHU = 21
 Question 195
What is the next number of the following sequence 90, 110, 132, 156, .....
 A 182 B 342 C 153 D 380
Question 195 Explanation:
10^2-10 = 90
11^2-11 = 110
12^2-12 = 132
13^2-13 = 156
same
14^2-14 = 182

 Question 196
Total cost of 2 rubbers and 3 pencils is greater than 20 rupee whereas total cost of 3 rubbers and 2 pencils is less than 24 rupee. If cost of pencil is less then 7 rupee then for what prize of rubber and pencil total cost of 4 rubbers and 5 pencils is minimum
 A 4, 4 B 2, 5 C 3, 4 D 3, 5
Question 196 Explanation:
2x+3y > 20
3x+2y < 24
y < 7
We have to find a condition such that 4x+5y is minimum
 Question 197
Total volume of a cylindrical tank (in litres), whose internal radius is 10 feet and height is 20 feet is (Given that 1 inch = 2.54 cm, 1000 cm3 = 1 litre and volume of a cylinder = 22 * (radius) 2 * height / 7)
 A 210324 B 177991 C 187654 D 156789
Question 197 Explanation:
Volume of a cylinder = 22 * (radius) 2 * height / 7
On taking all the values, we get V = 177991.61 litres

 Question 198
10 percent of 30 plus 30 percent of 10 =?
 A 26 B 10 C 8 D 6
Question 198 Explanation:
10% of 30 =3
30% of 10 = 3
6
 Question 199
Two equal amounts of money are deposited in two banks, each at 15% per annum, for 7/2 years and 5 years. If he difference between their interest is Rs.288, each sum is
 A 1620 B 1460 C 1280 D 640
Question 199 Explanation:
Let the sum be x. Then,
(x*5*15)/100 - x*15 * 7/2 * 1/100 = 288
x = 1280

 Question 200
If 2.0178 = 107 3.1980 = 681 4.6212 = 1568 5.2120 = 434 Then 6.1074 =
 A 1240 B 1475 C 197 D 99
Question 200 Explanation:
Here 2.0178 = 0178/2 + (2+0+1+7+8) = 89 + 18 = 107
Similarly for others
There are 200 questions to complete.