## Time And Work

Question 1 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

1200 | |

4500 | |

7200 | |

2400 |

^{100}/

_{10}= 10% of water per hour;

Quantity of water emptied per hour = 4 * 60 = 240;

Thus, 10% = 240 liter;

Hence, capacity of water,

100% = ^{240*100}/_{10} = 2400 liter.

Question 2 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

9 days | |

10 days | |

6 days | |

5 days |

**1**

^{st}Method: (A+B)'s one day's work = ^{1}/_{3} part;

(A+B) works 2 days together = ^{2}/_{3} part;

Remaining work = 1-(^{2}/_{3}) = ^{1}/_{3} part;

^{1}/_{3} part of work is completed by A in two days;

Hence, one day's work of A = ^{1}/_{6};

Then, one day's work of B = ^{1}/_{3} - ^{1}/_{6} = ^{1}/_{6};

So, B alone can complete the whole work in 6 days.

**2 ^{nd} method:**

(A+B)'s one day's % work = ^{100}/_{3} = 33.3%

Work completed in 2 days = 66.6%

Remaining work = 33.4%;

One day's % work of A = 33.4/2 = 16.7%;

One day's work of B = 33.3 - 16.7 = 16.7%;

B alone can complete the work in,

= ^{100}/_{16.7} = 6 days.

Question 3 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

12 days | |

10 days | |

15 days | |

8 days |

Question 4 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

15 | |

18 | |

16 | |

25 |

Question 5 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

120 days | |

72 days | |

100 days | |

80 days |

(x +11) *50 = (x +15) *45

→ x = 25

Thus, Total quantity of oil,

= (25 +11) *50

= 1800

Hence, required number of days,

= ^{1800}/_{25} = 72 days.

Question 6 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

8 | |

5 ^{1}/_{2} | |

5 | |

6 |

Question 7 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

5 days | |

10 days | |

40 days | |

20 days |

man*days*work = MAN*DAYS*WORK

10*20*1 = 20*2*x

→ x = 5 days.

Question 8 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

30 days | |

20 days | |

22 ^{1}/_{2} days | |

25 days |

Question 9 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

^{1}/

_{3}of actual efficiency, the work would have completed in 3 days. Find the for A to complete the job alone.

6 ^{3}/_{4} | |

6 ^{1}/_{4} | |

6 ^{1}/_{2} | |

12 ^{1}/_{2} |

^{1}/_{A} + ^{1}/_{B} = ^{1}/_{5}. ------ (i)

When A works with twice efficiency,Then,

^{2}/_{A} + ^{1}/_{3B} = ^{1}/_{3}. --------(ii)

on solving equations (i) and (ii), we get

A = ^{25}/_{4} = 6 ^{1}/_{4}.

Question 10 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें) |

19 | |

13 | |

21 | |

17 |

Total pay employee got = Rs. 829.

Total pay he gets if he did not remain idle a single day,

= 26 *56 = Rs.1456.

He Forfeits or fined = 1456 - 829 = Rs. 627.

Per day he Forfeits Rs. 7. Means per idle day he looses = 26 +7 = Rs. 33.

So, Total idle days = ^{627}/_{33} = 19 days.

**Alternatively,**

Let he works for X days and remain idle for (56 - X).

Now, According to question,

X*26 - 7*(56 -X)= 829.

26X + 7X - 392 = 829.

33X = 829 + 392 = 1221.

X = 37 days.

No of days remain idle = 56 -37 - 19 days.