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## Time And Work

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Question 1 |

1200 | |

4500 | |

7200 | |

2400 |

**Commerce Questions answers**

^{100}/

_{10}= 10% of water per hour;

Quantity of water emptied per hour = 4 * 60 = 240;

Thus, 10% = 240 liter;

Hence, capacity of water,

100% = ^{240*100}/_{10} = 2400 liter.

Question 2 |

9 days | |

10 days | |

6 days | |

5 days |

**Puzzles Questions answers**

**1**

^{st}Method:

(A+B)'s one day's work = ^{1}/_{3} part;

(A+B) works 2 days together = ^{2}/_{3} part;

Remaining work = 1-(^{2}/_{3}) = ^{1}/_{3} part;

^{1}/_{3} part of work is completed by A in two days;

Hence, one day's work of A = ^{1}/_{6};

Then, one day's work of B = ^{1}/_{3} - ^{1}/_{6} = ^{1}/_{6};

So, B alone can complete the whole work in 6 days.

**2 ^{nd} method:**

(A+B)'s one day's % work = ^{100}/_{3} = 33.3%

Work completed in 2 days = 66.6%

Remaining work = 33.4%;

One day's % work of A = 33.4/2 = 16.7%;

One day's work of B = 33.3 - 16.7 = 16.7%;

B alone can complete the work in,

= ^{100}/_{16.7} = 6 days.

Question 3 |

12 days | |

10 days | |

15 days | |

8 days |

**UPSC GS Questions answers**

Question 4 |

15 | |

18 | |

16 | |

25 |

**Economics Questions answers**

Question 5 |

120 days | |

72 days | |

100 days | |

80 days |

**NTA NET Questions answers**

(x +11) *50 = (x +15) *45

→ x = 25

Thus, Total quantity of oil,

= (25 +11) *50

= 1800

Hence, required number of days,

= ^{1800}/_{25} = 72 days.