Computer networking MCQ

1021. ..... is the physical layout of connected devices in a network.

Correct Answer: Correct answer is: (A) Network topology.

Exam Relevance: CCNA, Network+, CIW

Difficulty: Easy

Concept notes: Network topology refers to the physical layout of connected devices in a network.

Common Mistakes: Students may confuse network topology with network architecture, which is a broader term that includes the design and structure of the network, not just the physical layout.

Explanations: Network topology specifically describes the physical layout of devices in a network, such as how they are connected and arranged. This is distinct from network architecture, which encompasses a wider range of design and structural elements.

Option Analysis:

Option A: Correct. Network topology is the physical layout of connected devices in a network.
Option B: Incorrect. Network architecture is a broader term that includes the design and structure of the network, not just the physical layout.
Option C: Incorrect. Since network topology is the correct term, this option is not applicable.
Option D: Incorrect. Since network topology is the correct term, this option is not applicable.

1022. Documents in WWW can be grouped into three broad categories

Correct Answer: Correct answer is: (D) Static, dynamic, active.

Exam Relevance: Computer Science Exams, Web Development Exams, Information Technology Exams

Difficulty: Moderate

Concept notes: Documents in the World Wide Web (WWW) can be categorized into static, dynamic, and active based on their content and behavior.

Common Mistakes: Students may confuse the terms "static" and "dynamic" with the terms "stateless" and "stateful," which are related to web session management rather than document types.

Explanations: Static documents are those that do not change and are served as they are stored on the server. Dynamic documents are generated on the fly based on user input or other variables. Active documents involve user interaction and can change in real-time, such as web applications or interactive forms.

Option Analysis:

Option A: Incorrect because "double" is not a recognized category for web documents.
Option B: Incorrect because "stateless" and "archive" do not accurately describe the three broad categories of web documents.
Option C: Incorrect because "domain" and "architecture" are not categories of web documents.
Option D: Correct because "static," "dynamic," and "active" accurately describe the three broad categories of web documents.

Mnemonic: S.D.A. - Static, Dynamic, Active

1023. Sharing files with multiple computers at the same time takes a lot of effort from computer systems. One of the fastest and most cost-effective ways to share files is through which network model?

Correct Answer: Correct answer is: (A) Peer-to-Peer.

Exam Relevance: Networking Fundamentals, Computer Science Exams, IT Certification Exams

Difficulty: Easy

Concept notes: Peer-to-Peer (P2P) networks allow direct file sharing between multiple computers without the need for a central server, making it a cost-effective and efficient method for sharing files.

Common Mistakes: Students may confuse Peer-to-Peer with Client/Server models, where a central server is required for file sharing.

Explanations: Peer-to-Peer networks enable direct communication and file sharing between multiple computers, reducing the load on any single system and eliminating the need for a central server. This makes P2P a fast and cost-effective solution for sharing files among multiple computers simultaneously.

Option Analysis:

Option A: Peer-to-Peer networks allow direct file sharing between multiple computers, making it efficient and cost-effective.
Option B: Client/Server models require a central server to manage file sharing, which can be more resource-intensive.
Option C: Network Media refers to the physical or logical means of transmitting data, not a network model for file sharing.
Option D: Mainframe/Terminal models are outdated and not typically used for modern file sharing.

Mnemonic: P2P: Peer-to-Peer, Perfect for Peer file sharing.

1024. The X.25 standard specifies a.....

Correct Answer: Correct answer is: (C) DTE/DCE interface.

Exam Relevance: CCNA, CompTIA Network+, CISSP

Difficulty: Moderate

Concept notes: The X.25 standard is a set of protocols for wide area networks (WANs) and defines the interface between data terminal equipment (DTE) and data circuit-terminating equipment (DCE).

Common Mistakes: Students may confuse X.25 with other data communication standards or protocols, such as those used for dial access or start-stop data transmission.

Explanations: The X.25 standard specifies the DTE/DCE interface, which is crucial for establishing and managing connections between network devices. This interface defines the physical and logical connection between the user's equipment (DTE) and the network provider's equipment (DCE). The standard ensures compatibility and interoperability between different devices and networks.

Option Analysis:

Option A: X.25 does not specify a technique for start-stop data transmission. This is more related to asynchronous communication protocols.
Option B: X.25 is not concerned with dial access techniques. Dial access is typically associated with protocols like PPP (Point-to-Point Protocol).
Option C: X.25 defines the DTE/DCE interface, which is the correct answer.
Option D: This option is incorrect as X.25 does specify the DTE/DCE interface.

Mnemonic: X.25 DTE/DCE, Think "Data Terminal and Circuit Equipment"

1025. What does BAHO stands for?

Correct Answer: Correct answer is: (A) Base station assisted handover.

Exam Relevance: GATE, GRE, Professional Certification Exams

Difficulty: Very Easy

Concept notes: BAHO stands for Base Station Assisted Handover, a term used in telecommunications to describe a process where a base station assists in the handover of a mobile device from one cell to another.

Common Mistakes: Students may confuse BAHO with other similar terms like BHO (Base Handover) or BAH (Base Assisted Handover), leading to incorrect answers.

Explanations: BAHO is the correct term for Base Station Assisted Handover, which is a process where the base station plays a crucial role in facilitating the handover of a mobile device from one cell to another. This ensures seamless communication as the device moves between different coverage areas.

Option Analysis:

Option A: Correct. BAHO stands for Base Station Assisted Handover.
Option B: Incorrect. The term "Base assisted handover" is not the correct acronym for BAHO.
Option C: Incorrect. The term "Base assistance handover" is not the correct acronym for BAHO.
Option D: Incorrect. The correct answer is provided in Option A.

1026. The VPI of a UNI is..... bits in length.

Correct Answer: Correct answer is: (A) 8.

Exam Relevance: Computer Networks, Telecommunications, Data Communication

Difficulty: Very Easy

Concept notes: The VPI (Virtual Path Identifier) of a UNI (User Network Interface) is a component of the ATM (Asynchronous Transfer Mode) addressing scheme.

Common Mistakes: Students may confuse the VPI length with the VCI (Virtual Channel Identifier) length, which is typically 16 bits.

Explanations: The VPI in a UNI is 8 bits in length. This is a standard specification in ATM networks, where the VPI is used to identify virtual paths in the network. The VCI, which is 16 bits, is used to identify virtual channels within those paths.

Option Analysis:

Option A: Correct. The VPI at a UNI is 8 bits.
Option B: Incorrect. 12 bits is not the standard length for VPI at a UNI.
Option C: Incorrect. 16 bits is the length of the VCI, not the VPI.
Option D: Incorrect. 24 bits is not the standard length for VPI at a UNI.

Mnemonic: VPI is "V"ery "P"ath "I"dentifiable, 8 bits.

1027. To pipeline packet transmission across the circuit using staging at each hop along the path, a technique known as

Correct Answer: Correct answer is: (A) Pipelined circuit switching.

Exam Relevance: Computer Networks, Data Communications, Network Fundamentals

Difficulty: Moderate

Concept notes: Pipelined circuit switching is a technique that allows for the efficient transmission of packets by staging at each hop along the path, thereby reducing the overall transmission delay.

Common Mistakes: Students may confuse pipelined circuit switching with traditional circuit switching, which does not involve staging at each hop.

Explanations: Pipelined circuit switching is a technique that enhances the efficiency of packet transmission in a network. It involves staging packets at each hop along the path, allowing for the pipeline effect where multiple packets can be in transit simultaneously. This reduces the overall delay and improves the throughput of the network. Traditional circuit switching, on the other hand, establishes a dedicated path for the entire duration of the communication, without the benefit of pipelining. Livelock avoidance is a different concept related to preventing processes from continuously failing to make progress, which is not directly related to packet transmission techniques.

Option Analysis:

Option A: Correct. Pipelined circuit switching is the technique that allows for staging at each hop along the path, improving packet transmission efficiency.
Option B: Incorrect. Livelock avoidance is a concept related to process management and not packet transmission techniques.
Option C: Incorrect. Circuit switching is a traditional technique that does not involve pipelining or staging at each hop.
Option D: Incorrect. The correct answer is explicitly provided as Option A.

1028. A traditional cable TV network transmits signals.....

Correct Answer: Correct answer is: (B) Downstream.

Exam Relevance: Networking exams, Telecommunications exams, Information Technology exams

Difficulty: Easy

Concept notes: Traditional cable TV networks transmit signals in a downstream direction, meaning the signals flow from the provider to the end user.

Common Mistakes: Students may confuse the direction of signal transmission, thinking it can be bidirectional or upstream.

Explanations: In a traditional cable TV network, the signal flows from the cable provider to the end user's television. This is known as downstream transmission. The provider sends the TV channels to the user's home, and there is no need for the user to send signals back to the provider for this basic service.

Option Analysis:

Option A: Incorrect, as traditional cable TV networks do not transmit signals upstream.
Option B: Correct, as traditional cable TV networks transmit signals downstream.
Option C: Incorrect, as traditional cable TV networks do not require both upstream and downstream transmission for basic service.
Option D: Incorrect, as downstream transmission is a valid and correct answer.

Mnemonic: Downstream: "D" for "Direct to you."

1029. Which of the following two mediums has a higher bandwidth?

Correct Answer: Correct answer is: (A) Fibre.

Exam Relevance: Networking exams, Telecommunications exams, Computer Science exams

Difficulty: Moderate

Concept notes: Fibre optic cables have a higher bandwidth compared to copper cables due to their ability to transmit data over longer distances with less signal degradation.

Common Mistakes: Students often confuse the physical properties of copper and fibre, leading to incorrect assumptions about their bandwidth capabilities.

Explanations: Fibre optic cables use light to transmit data, which allows for higher bandwidth and less signal loss over long distances. Copper cables, on the other hand, use electrical signals, which can suffer from interference and signal degradation over longer distances, limiting their bandwidth.

Option Analysis:

Option A: Fibre optic cables have a higher bandwidth due to their use of light for data transmission.
Option B: Copper cables have a lower bandwidth due to signal degradation over long distances.
Option C: This option is incorrect as fibre has a higher bandwidth than copper.
Option D: This option is incorrect as fibre has a higher bandwidth than copper.

Mnemonic: Light travels fast, Fibre wins the race.

1030. First address in block can be found by setting rightmost 32-n bits to

Correct Answer: Correct answer is: (A) Os.

Exam Relevance: Computer Architecture, Operating Systems, Data Structures

Difficulty: Easy

Concept notes: In computer memory addressing, setting the rightmost bits to 0s in a block address gives the first address in that block.

Common Mistakes: Students may confuse setting bits to 1s, thinking it would give the first address.

Explanations: To find the first address in a block, the rightmost bits are set to 0s. This is because the rightmost bits represent the offset within the block, and setting them to 0s gives the starting address of the block.

Option Analysis:

Option A: Correct. Setting the rightmost bits to 0s gives the first address in the block.
Option B: Incorrect. Setting the rightmost bits to 1s would give the last address in the block, not the first.
Option C: Incorrect. A combination of 0s and 1s would not give a consistent first address in the block.
Option D: Incorrect. Null is not a valid option for setting bits in an address.

⬅ Previous SetSet 103Next Set ➡

Computer networking MCQ - Set 103

Leave a Reply