Computer networking MCQ

1291. According to the Nyquist theore, M we need to sample an analog signal.....times the highest frequency.

Correct Answer: Correct answer is: (B) Two.

Exam Relevance: EEG, ECE, DSP, Signal Processing Exams

Difficulty: Easy

Concept notes: The Nyquist theorem states that to accurately reconstruct an analog signal, it must be sampled at a rate at least twice the highest frequency component of the signal.

Common Mistakes: Students often confuse the Nyquist rate with other sampling rates or forget the exact factor required.

Explanations: The Nyquist theorem specifies that the sampling rate must be at least twice the highest frequency component of the signal to avoid aliasing and ensure accurate reconstruction. This is known as the Nyquist rate. Therefore, the correct answer is two.

Option Analysis:

Option A: Incorrect, as the Nyquist theorem specifies a factor of two, not three.
Option B: Correct, as the Nyquist theorem specifies a factor of two.
Option C: Incorrect, as the Nyquist theorem specifies a factor of two, not four.
Option D: Incorrect, as the correct answer is explicitly stated in the theorem.

1292. A unique name that identifies a website is called a.....

Correct Answer: Correct answer is: (A) Domain name.

Exam Relevance: SAT, ACT, AP Computer Science Principles

Difficulty: Easy

Concept notes: A domain name is a unique name that identifies a website on the internet.

Common Mistakes: Students may confuse domain names with IP addresses, which are numerical identifiers for devices on a network.

Explanations: A domain name is a human-readable address that corresponds to a website's IP address. It is unique and helps users easily access websites without needing to remember complex IP addresses.

Option Analysis:

Option A: Correct. A domain name is a unique name that identifies a website.
Option B: Incorrect. Browsers are software applications used to access websites, not unique identifiers.
Option C: Incorrect. IP addresses are numerical identifiers for devices on a network, not unique names for websites.
Option D: Incorrect. HTML is a markup language used to structure web pages, not a unique identifier for websites.

Mnemonic: Domain Name: Dot Net, Dot Com, Dot Org

1293. Consider the following Statements: A LAN can span several sites over a global area star networks generally require more cable than bus networks. TCP / IP is the internet communication protocol. Which of the following statement(s) is/are true?

Correct Answer: Correct answer is: (D) Only 2, 3.

Exam Relevance: CCNA, CISSP, CompTIA Network+

Difficulty: Moderate

Concept notes: The correct answer is based on the understanding of LAN characteristics, network topologies, and communication protocols.

Common Mistakes: Students may incorrectly assume that a LAN can span a global area, which is not true as LANs are typically confined to a small geographical area.

Explanations: Statement 1 is incorrect because a LAN (Local Area Network) is designed to cover a small geographical area, such as a single building or a group of buildings. It cannot span several sites over a global area, which would be more characteristic of a WAN (Wide Area Network). Statement 2 is correct because star networks generally require more cable than bus networks. In a star topology, each device is connected to a central hub or switch, which means each device needs its own cable. In contrast, a bus topology uses a single cable to connect all devices, requiring less cable overall. Statement 3 is correct because TCP/IP (Transmission Control Protocol/Internet Protocol) is indeed the standard communication protocol used on the internet. It provides the rules and procedures for data transmission over the internet. Therefore, the correct answer is D) Only 2, 3.

Option Analysis:

Option A: Incorrect because statement 1 is false.
Option B: Incorrect because statement 1 is false.
Option C: Incorrect because statement 1 is false.
Option D: Correct because statements 2 and 3 are true.

1294. In..... transmission, the phase of the carrier signal is modulated to follow the changing voltage level (amplitude) of the modulating signal.

Correct Answer: Correct answer is: (B) PM.

Exam Relevance: GATE, ECE, EE

Difficulty: Moderate

Concept notes: Phase Modulation (PM) involves changing the phase of the carrier signal in response to the modulating signal's amplitude.

Common Mistakes: Students often confuse Phase Modulation (PM) with Frequency Modulation (FM), where the frequency rather than the phase is modulated.

Explanations: In Phase Modulation (PM), the phase of the carrier signal is modulated to follow the changing voltage level (amplitude) of the modulating signal. This means that the phase deviation of the carrier is proportional to the amplitude of the modulating signal. This is different from Amplitude Modulation (AM) where the amplitude of the carrier is varied, and Frequency Modulation (FM) where the frequency of the carrier is varied.

Option Analysis:

Option A: AM involves varying the amplitude of the carrier signal, not the phase.
Option B: PM involves varying the phase of the carrier signal in response to the modulating signal's amplitude.
Option C: FM involves varying the frequency of the carrier signal, not the phase.
Option D: This option is incorrect as PM is the correct answer.

Mnemonic: PM: Phase Moves

1295. A SMTP session may include

Correct Answer: Correct answer is: (D) All of the mentioned.

Exam Relevance: Network+ Certification, CCNA, CISSP

Difficulty: Moderate

Concept notes: An SMTP session can include zero, one, or more than one SMTP transaction.

Common Mistakes: Students may incorrectly assume that an SMTP session must always include at least one transaction.

Explanations: An SMTP session is a communication between an SMTP client and server. It can be initiated without any transactions, meaning no emails are sent (zero transactions). It can also include a single transaction where one email is sent, or multiple transactions where multiple emails are sent. Therefore, the correct answer is that an SMTP session may include zero, one, or more than one SMTP transaction.

Option Analysis:

Option A: An SMTP session can indeed have zero transactions, such as when the session is initiated but no emails are sent.
Option B: An SMTP session can have one transaction, which is the case when a single email is sent.
Option C: An SMTP session can have more than one transaction, which occurs when multiple emails are sent in a single session.
Option D: This option correctly encompasses all the possibilities for the number of transactions in an SMTP session.

1296. In Normal Response Mode (NRM), station configuration is

Correct Answer: Correct answer is: (B) Unbalanced.

Exam Relevance: Computer Networks, Data Communication, Network Protocols

Difficulty: Moderate

Concept notes: In Normal Response Mode (NRM), the station configuration is unbalanced, meaning that the stations are not symmetrically configured in terms of their roles and responsibilities.

Common Mistakes: Students often confuse NRM with other modes where station configurations might be balanced or symmetric.

Explanations: In NRM, the stations are configured such that one station acts as the primary sender and the other as the primary receiver. This asymmetry in roles makes the configuration unbalanced. The primary sender initiates the communication and the primary receiver responds, leading to an unbalanced setup.

Option Analysis:

Option A: Incorrect because the stations are not symmetrically configured in NRM.
Option B: Correct because the stations have different roles, making the configuration unbalanced.
Option C: Incorrect because zero configuration does not apply to NRM.
Option D: Incorrect because the configuration is well-defined in NRM.

1297. In Satellite Networks, as we move out of footprint center, power

Correct Answer: Correct answer is: (A) Decreases.

Exam Relevance: GATE, GRE, ECE Exams

Difficulty: Easy

Concept notes: In satellite networks, the power received at a ground station decreases as the distance from the satellite's footprint center increases.

Common Mistakes: Students may mistakenly believe that power remains constant or increases as they move away from the footprint center.

Explanations: The power received by a ground station in a satellite network is highest at the footprint center due to the direct line-of-sight and minimal signal attenuation. As the distance from the footprint center increases, the signal path becomes longer and more oblique, leading to increased signal attenuation and thus a decrease in received power.

Option Analysis:

Option A: Correct. Power decreases as distance from the footprint center increases.
Option B: Incorrect. Power does not increase as distance from the footprint center increases.
Option C: Incorrect. Power is not constant as distance from the footprint center increases.
Option D: Incorrect. This option is not applicable as the correct answer is provided.

Mnemonic: Power Drop, Far From Center

1298. If you want to have more than one Telnet session open at the same time, what keystroke combination would you use?

Correct Answer: Correct answer is: (D) Ctrl+Shift+6, then X.

Exam Relevance: CCNA, CompTIA Network+, Cisco certifications

Difficulty: Moderate

Concept notes: The correct answer involves a specific keystroke combination used in Telnet sessions to manage multiple connections.

Common Mistakes: Students often confuse the keystroke combinations for different terminal operations, leading to incorrect usage.

Explanations: In Telnet, the keystroke combination Ctrl+Shift+6, then X is used to open a new session while maintaining the current session. This allows for multiple Telnet sessions to be open simultaneously. The combination is a standard method for managing multiple connections in Telnet environments.

Option Analysis:

Option A: Tab+Spacebar is not a recognized combination for managing Telnet sessions.
Option B: Ctrl+X, then 6 is not the correct combination for opening a new Telnet session.
Option C: Ctrl+Shift+X, then 6 is not the correct combination for opening a new Telnet session.
Option D: Ctrl+Shift+6, then X is the correct combination for opening a new Telnet session.

Mnemonic: TEN-6X: Telnet, Enter New, 6X

1299. Computers on the Internet owned and operated by education institution form part of the

Correct Answer: Correct answer is: (B) Edu domain.

Exam Relevance: CISSP, CompTIA Network+, CCNA

Difficulty: Easy

Concept notes: The edu domain is specifically designated for educational institutions.

Common Mistakes: Students may confuse the edu domain with other domains like com or org.

Explanations: The edu domain is reserved for educational institutions. Computers owned and operated by educational institutions are part of the edu domain. This domain is specifically designated for schools, universities, and other educational organizations.

Option Analysis:

Option A: The com domain is for commercial entities, not educational institutions.
Option B: The edu domain is correct as it is reserved for educational institutions.
Option C: The mil domain is for military organizations, not educational institutions.
Option D: This option is incorrect as the edu domain is the correct answer.

Mnemonic: Edu for Education, Easy to Remember

1300. What is the method of access in bluetooth?

Correct Answer: Correct answer is: (C) TDD-TDMA.

Exam Relevance: IEEE 802.15.1, Wireless Communication Exams, Computer Networks Exams

Difficulty: Moderate

Concept notes: Bluetooth uses a method of access called Time Division Duplex-Time Division Multiple Access (TDD-TDMA) to manage communication between devices.

Common Mistakes: Students may confuse TDD-TDMA with other multiple access techniques like CDMA or FDMA, which are used in different wireless communication systems.

Explanations: Bluetooth employs TDD-TDMA to allow multiple devices to communicate over the same frequency band without interference. In TDD-TDMA, time is divided into slots, and each device is assigned a specific time slot for transmission and reception. This ensures that devices do not transmit simultaneously, thereby avoiding collisions and ensuring efficient use of the frequency band.

Option Analysis:

Option A: CDMA (Code Division Multiple Access) is not used in Bluetooth. It is typically used in cellular networks.
Option B: FDMA (Frequency Division Multiple Access) is not used in Bluetooth. It is used in older cellular systems.
Option C: TDD-TDMA (Time Division Duplex-Time Division Multiple Access) is the correct method used in Bluetooth for managing access to the shared frequency band.
Option D: CD (Carrier Division) is not a recognized method of access in Bluetooth.

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Computer networking MCQ - Set 130

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