Computer networking MCQ

1301. The entire hostname has a maximum of

Correct Answer: Correct answer is: (A) 255 characters.

Exam Relevance: CCNA, CISSP, CompTIA Network+

Difficulty: Moderate

Concept notes: The hostname in a domain name system (DNS) has a maximum length of 255 characters.

Common Mistakes: Students often confuse the maximum length of a single label within a hostname (which is 63 characters) with the total length of the hostname.

Explanations: The entire hostname, including all labels and periods, can be up to 255 characters long. This is a standard defined by the DNS protocol. Each label within the hostname can be up to 63 characters, but the total length of the hostname, including the periods separating the labels, cannot exceed 255 characters.

Option Analysis:

Option A: Correct. The entire hostname can be up to 255 characters long.
Option B: Incorrect. 127 characters is not the maximum length for the entire hostname.
Option C: Incorrect. 63 characters is the maximum length for a single label within the hostname, not the entire hostname.
Option D: Incorrect. 31 characters is not the maximum length for the entire hostname.

1302. In SCTP, ..... can be carried in a packet that carries an INIT chunk.

Correct Answer: Correct answer is: (C) No other chunk.

Exam Relevance: Computer Networks, Network Protocols, SCTP

Difficulty: Moderate

Concept notes: In SCTP (Stream Control Transmission Protocol), the INIT chunk is used to initiate a new association between two endpoints. The INIT chunk is critical for establishing the initial connection parameters and must be processed before any other data or control chunks can be exchanged.

Common Mistakes: A common misunderstanding is that data or other control chunks can be included in the same packet as the INIT chunk, but this is not allowed by the SCTP protocol.

Explanations: The SCTP protocol specifies that the INIT chunk must be sent in a separate packet and cannot be combined with any other chunks, including data or other control chunks. This ensures that the initial connection setup is completed before any other communication takes place.

Option Analysis:

Option A: Incorrect because data chunks cannot be carried in the same packet as the INIT chunk.
Option B: Incorrect because control chunks other than INIT cannot be carried in the same packet as the INIT chunk.
Option C: Correct because the INIT chunk must be sent in a separate packet without any other chunks.
Option D: Incorrect because the correct answer is explicitly stated in option C.

1303. X.25 has a data rate of

Correct Answer: Correct answer is: (B) 64-kbps.

Exam Relevance: Computer Networks, Data Communications, CCNA, CISSP

Difficulty: Easy

Concept notes: X.25 is a standard for packet-switched networks and typically operates at a data rate of 64 kbps.

Common Mistakes: Students may confuse X.25 data rates with other network standards or protocols.

Explanations: X.25 is a packet-switched network protocol that was widely used in the early days of the internet. It operates at a standard data rate of 64 kbps, which is the correct answer. This data rate is a well-established characteristic of the X.25 protocol.

Option Analysis:

Option A: 32-kbps is not the standard data rate for X.25.
Option B: 64-kbps is the correct standard data rate for X.25.
Option C: 68-kbps is not a standard data rate for X.25.
Option D: 92-kbps is not a standard data rate for X.25.

Mnemonic: X.25, 64, Net Speed

1304. IO devices which enable user to communicate with computer system are called

Correct Answer: Correct answer is: (A) Terminals.

Exam Relevance: Computer Science Fundamentals, Networking Exams, IT Certification Exams

Difficulty: Easy

Concept notes: Terminals are devices that allow users to interact with a computer system, typically through input and output operations.

Common Mistakes: Students may confuse terminals with other communication devices or buses, which do not directly facilitate user interaction with the computer system.

Explanations: Terminals are specifically designed to enable user interaction with a computer system. They provide a means for users to input commands and receive output, making them the correct choice for devices that enable user communication with a computer system.

Option Analysis:

Option A: Terminals are correct as they are designed for user interaction with a computer system.
Option B: Telecommunication refers to the transmission of information over a distance, not specifically to user interaction with a computer system.
Option C: Buses are internal pathways for data transfer within a computer system, not for user interaction.
Option D: Communication devices are a broader category that includes various types of devices, not specifically those for user interaction with a computer system.

Mnemonic: Terminals = Talk to Computers

1305. You want to run the new 802.1w on your switches. Which of the following would enable this protocol?

Correct Answer: Correct answer is: (A) Switch(config)# spanning-tree mode rapid-pvst.

Exam Relevance: CCNA, CCNP, Network+

Difficulty: Moderate

Concept notes: The 802.1w protocol is also known as Rapid Spanning Tree Protocol (RSTP). The command to enable RSTP on a switch is "spanning-tree mode rapid-pvst".

Common Mistakes: Students may confuse the command with the standard PVST+ mode or the 802.1w protocol name, leading to incorrect configuration.

Explanations: The correct command to enable the 802.1w protocol, which is Rapid Spanning Tree Protocol (RSTP), is "spanning-tree mode rapid-pvst". This command must be entered in the global configuration mode of the switch, indicated by the "(config)" prompt. The other options are incorrect because they either use the wrong command syntax or are not in the correct configuration mode.

Option Analysis:

Option A: Correct command to enable RSTP in global configuration mode.
Option B: Incorrect because it is not in the global configuration mode.
Option C: Incorrect because it uses the 802.1w protocol name instead of the correct RSTP command.
Option D: Incorrect because it is not in the global configuration mode and uses the 802.1w protocol name.

Mnemonic: Rapid PVST, not 802.1w, for RSTP.

1306. Which of the following is correct in VLSM(Variable-Length Subnet Masking)?

Correct Answer: Correct answer is: (A) Can have subnets of different sizes.

Exam Relevance: CCNA, CISSP, CompTIA Network+

Difficulty: Easy

Concept notes: VLSM (Variable-Length Subnet Masking) allows for the creation of subnets of varying sizes within a single network.

Common Mistakes: Students often confuse VLSM with fixed subnetting, where all subnets are of the same size.

Explanations: VLSM is a technique that allows network administrators to create subnets of different sizes from a single IP address space. This flexibility is crucial for efficient use of IP addresses, especially in large networks where different subnets may require different numbers of IP addresses. By allowing subnets of different sizes, VLSM optimizes the allocation of IP addresses and reduces waste.

Option Analysis:

Option A: Correct. VLSM allows for subnets of different sizes.
Option B: Incorrect. VLSM does not require subnets to be the same size.
Option C: Incorrect. VLSM requires the use of subnets.
Option D: Incorrect. Not all options are correct.

Mnemonic: VLSM: Variable Length, Subnets Mix

1307. VPNs are financially speaking.....

Correct Answer: Correct answer is: (C) Usually cheaper than leased lines.

Exam Relevance: CISSP, CCNA, CompTIA Network+

Difficulty: Moderate

Concept notes: Virtual Private Networks (VPNs) are generally more cost-effective than leased lines for establishing secure connections over the internet.

Common Mistakes: Students may mistakenly believe that leased lines are always cheaper because they are dedicated connections, but this overlooks the operational and maintenance costs associated with leased lines.

Explanations: VPNs are usually cheaper than leased lines because they leverage existing internet infrastructure, reducing the need for dedicated, expensive physical connections. Leased lines, while offering higher security and performance, come with higher costs due to the need for dedicated hardware and maintenance. The cost savings of using a shared network (internet) for a VPN make it a more economical choice for many organizations.

Option Analysis:

Option A: Incorrect because leased lines are typically more expensive due to dedicated hardware and maintenance costs.
Option B: Incorrect because while cheaper in many cases, it is not always the case due to varying network requirements and costs.
Option C: Correct because the shared infrastructure of the internet makes VPNs generally more cost-effective than leased lines.
Option D: Incorrect because leased lines are usually more expensive due to the dedicated nature of the connection.

Mnemonic: V for Value, P for Practical, N for Network

1308. Distance of Symmetric Digital Subscriber Line (SDSL) is

Correct Answer: Correct answer is: (B) 12000.

Exam Relevance: Networking exams, Telecommunications exams, Computer Science exams

Difficulty: Moderate

Concept notes: The distance of Symmetric Digital Subscriber Line (SDSL) is a key parameter in understanding its operational capabilities and limitations.

Common Mistakes: Students often confuse the distance capabilities of different DSL technologies, such as ADSL and SDSL, leading to incorrect assumptions about their range.

Explanations: Symmetric Digital Subscriber Line (SDSL) is a type of DSL technology that provides equal data transfer rates for both upstream and downstream traffic. The maximum distance for SDSL is typically around 12,000 feet (approximately 3,658 meters). This distance is determined by the physical limitations of the twisted-pair copper wires used in the telephone network. The claimed correct answer of 12,000 feet is consistent with the standard operational range of SDSL technology.

Option Analysis:

Option A: 18000 feet is incorrect as it exceeds the typical operational range of SDSL.
Option B: 12000 feet is the correct distance for SDSL, aligning with its operational capabilities.
Option C: 10000 feet is too low and does not reflect the full operational range of SDSL.
Option D: 30000 feet is incorrect as it far exceeds the typical operational range of SDSL.

1309. The number of objects in a Web page which consists of 4 jpeg images and HTML text is.....

Correct Answer: Correct answer is: (C) 5.

Exam Relevance: Computer Science Fundamentals, Web Development Exams

Difficulty: Easy

Concept notes: A Web page consists of multiple objects, including images and text. Each JPEG image is considered a separate object, and the HTML text is also considered an object.

Common Mistakes: Students may mistakenly count only the images and overlook the HTML text as a separate object.

Explanations: A Web page with 4 JPEG images and HTML text contains 5 objects in total. Each JPEG image is counted as one object, and the HTML text is counted as a separate object. Therefore, the total number of objects is 4 (JPEG images) + 1 (HTML text) = 5.

Option Analysis:

Option A: Incorrect, as it only counts the images and not the HTML text.
Option B: Incorrect, as it only counts the entire page as one object, ignoring the individual components.
Option C: Correct, as it counts each JPEG image and the HTML text as separate objects.
Option D: Incorrect, as the correct answer is explicitly provided.

1310. Slotted ALOHA

Correct Answer: Correct answer is: (C) Both (a) and (b).

Exam Relevance: Computer Networks, Data Communications, Network Protocols

Difficulty: Moderate

Concept notes: Slotted ALOHA is a protocol used in computer networks for managing access to a shared communication channel. It divides time into discrete intervals and requires global time synchronization to ensure that all nodes transmit data in the same time slots.

Common Mistakes: Students often confuse Slotted ALOHA with Pure ALOHA, which does not divide time into discrete intervals and does not require global time synchronization.

Explanations: Slotted ALOHA divides time into discrete intervals, which is a key feature of the protocol. Additionally, it requires global time synchronization to ensure that all nodes transmit data in the same time slots. Therefore, both (a) and (b) are correct.

Option Analysis:

Option A: Slotted ALOHA does divide time into discrete intervals, which is correct.
Option B: Slotted ALOHA does require global time synchronization, which is also correct.
Option C: Both (a) and (b) are correct, making this the correct answer.
Option D: This option is incorrect as both (a) and (b) are true.

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Computer networking MCQ - Set 131

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