# Clocks Calender and Age

By | April 20, 2019

## Clock and calender

 Question 1 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
What is the angle between the two hands of a clock when the time shown by the clock is 5.30 p.m.?
 [A] $0^\circ$ [B] $5^\circ$ [C] $3^\circ$ [D] $15^\circ$
Explanation:
q = 11/2 m – 30h = 11/2 *30 - 30 *5 = 165-150 = $15^\circ$
 Question 2 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
By how many degrees does the minute hand move in the same time, in which the hour hand move by 18 degree?
 [A] 168 degree [B] 216 degree [C] 196 degree [D] 276 degree
Explanation:
18*2 *6 = 216 degree
 Question 3 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
A watch, which loses time uniformly, was observed to be 5 minutes fast at 8.00 p.m. On Thursday. It was noticed to be 7 minutes slow at 8.00 a.m. on the subsequent Monday. When did the watch show the correct time?
 [A] 7 a.m. Saturday [B] 7 a.m. on Friday [C] 10 a.m. on Sunday [D] 11 a.m. on Friday
Explanation:
The number of hours from 8:00 p.m. on Thursday to 8:00 a.m. on Monday = 84 hours. In 84 hours, the clock gained 12 minutes. But to show the correct time, the clock has to gain 5 minutes. :. 5/12 *84 = 35 hours. 35 hours from 8:00 p.m. on Thursday is 7:00 a.m. on Saturday.
 Question 4 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
In the time in which the second hand covers 3960 degrees, how many degrees does the hour hand move?
 [A] 11 [B] 5.5 [C] 3/4 [D] 5/3
Explanation:
$3960/(360*2) = 5.5^\circ$
 Question 5 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
By how many degrees does the hour hand lag behind the minute hand in a span of 42 minutes, if initially they are at the same position?
 [A] $233^\circ$ [B] $211^\circ$ [C] $231^\circ$ [D] $235^\circ$
Explanation:
42*6-(42/2) = 252-21 = 231 degree
 Question 6 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
March 1st  is Wednesday. Which month of the same year has the same calendar
 [A] July [B] November [C] December [D] October
Explanation:
Odd days from March to October : 3 + 2 +3 +2 +3 +3 +2 +3 = 21/7 = 0 . If odd day is 0 then next month has the same calendar.
 Question 7 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
If today is Thursday, after 730 days which will be the day of the week?
 [A] Thursday [B] Friday [C] Saturday [D] Monday
Explanation:
730/7 = 2 odd days. So Saturday will be the day of the week.
 Question 8 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
A year starting with Monday and ending with Tuesday. How many days are there  from 16th January to 15th March of  that year.
 [A] 58 [B] 59 [C] 60 [D] 61
Explanation:
It is a leap year. So 16(Jan)+ 29(Feb) + 15(March) = 60 days
 Question 9 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
The last day of a century cannot be:
 [A] Monday [B] Wednesday [C] Friday [D] Saturday
Explanation:
100 years contains 5 odd days. So last day of 1st century is ‘Friday’. 200 years contains (5*2) =10 = 3 odd days. So last day of second century is ‘Wednesday’. 300 years contain 15 odd days = 1 odd day. . : Last day of 3rd century is ‘Monday’. 400 years contains 0 odd day. : . Last day of 4th century is ‘Sunday’. Since the order is continually kept in successive cycles, we see that the last day of a century cannot be Tuesday, Thursday or Saturday
 Question 10 ->Click on any option to know the correct answers (सही उत्तर जानने के लिए किसी भी Choice पर क्लिक करें)
What will be the day of the week on 1st January, 2010?
 [A] Friday [B] Saturday [C] Sunday [D] Monday
Explanation:
2000 years have 2 odd days. Number of odd days from 2001 –2009 = 11 odd days = 4 odd days. 1st January. 2010 has 1 odd day. Total number of odd days = (2 + 4 + 1) = 7 = 0 odd day : . 1st January, 2010 will be a Sunday.
There are 10 questions to complete.