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Ratio
Question 101 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
A track covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33 kms in 45 minute. The ratio of their speeds is:
3:4 | |
3:5 | |
4:3 | |
50:3 |
Question 101 Explanation:
Speed of track = 550 per minute.
Speed of bus = 33 kms /45 = 33000/45 = 733.33 m/minute
Ratio of their speeds = 550/733.33 = 3:4.
Question 102 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
If A : B = 2 : 3, B : C = 2 : 4 and C : D = 2 : 5, then A : D is equal to -
1 : 5 | |
3 : 5 | |
2 : 5 | |
2 : 15 |
Question 102 Explanation:
\begin{align} & = \frac{{\text{A}}}{{\text{B}}} = \frac{2}{3}, \, \frac{{\text{B}}}{{\text{C}}} = \frac{2}{4}, \, \frac{{\text{C}}}{{\text{D}}} = \frac{2}{5} \cr & \Rightarrow \frac{{\text{A}}}{{\text{D}}} = \left( {\frac{{\text{A}}}{{\text{B}}} \times \frac{{\text{B}}}{{\text{C}}} \times \frac{{\text{C}}}{{\text{D}}}} \right) \cr & \Rightarrow \frac{2}{3} \times \frac{2}{4} \times \frac{2}{5} = \frac{2}{{15}} \cr & \Rightarrow {\text{A}}:{\text{D}} = 2:15. \cr\end{align}
Question 103 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
$\frac{3}{4}:\frac{1}{2}::27y:?\, {\text{Solve}}\, {\text{this - }}$
24y | |
12y | |
21y | |
18y |
Question 103 Explanation:
Let the missing number be x.
Then, \begin{align} & = \frac{1}{3}:\frac{1}{2}::27y:x \cr & \Rightarrow \frac{3}{4}x = \frac{1}{2} \times {\text{27}}y \cr & \Rightarrow x{\text{ = }}\frac{{27y}}{2} \times \frac{4}{3} \cr & = 18y. \cr\end{align}
Question 104 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
94 is divided into two parts in such a way that fifth part of the first and the eighth part of the second are in the ratio 3 : 4. The first part is =?
36 | |
28 | |
40 | |
30 |
Question 104 Explanation:
\begin{align} & {\text{A}} + {\text{B}} = 94 \cr & \therefore \frac{{\text{A}}}{5}:\frac{{\text{B}}}{8} = 3:4 \cr & \Rightarrow \frac{{{\text{A}} \times 8}}{{5 \times {\text{B}}}} = \frac{3}{4} \cr & \Rightarrow \frac{{\text{A}}}{{\text{B}}} = \frac{3}{4} \times \frac{5}{8} \cr & \Rightarrow \frac{{\text{A}}}{{\text{B}}} = \frac{{15}}{{32}} \cr & {\text{ A}}:{\text{B}} \cr & {\text{ }}15:32 \cr & {\text{Let }}15x:32x \cr & \therefore 15x + 32x = 47x \cr & \Rightarrow 47x = 94 \cr & \Rightarrow x = 2 \cr & \therefore {\text{A}} = 2 \times 15 = 30 \cr & {\text{B}} = 32 \times 2 = 64 \cr\end{align}
Question 105 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
In an innings of a cricket match, three players A, B and C scored a total of 361 runs. If the ratio of the number of runs scored by A to that scored by B and also number of runs scored by B to that scored by C be 3 : 2, the number of runs scored by A was -
171 | |
181 | |
161 | |
185 |
Question 105 Explanation:
\begin{align} & {\text{A}}:{\text{B}} = 3:2, \cr & {\text{B}}:{\text{C = }}3:2 \cr & = \left( {3 \times \frac{2}{3}} \right):\left( {2 \times \frac{2}{3}} \right) \cr & = 2:\frac{4}{3}. \cr & {\text{A}}:{\text{B}}:{\text{C}} = 3:2:\frac{4}{3} \cr & \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, = 9:6:4 \cr & \therefore {\text{A's score}} = \left( {361 \times \frac{9}{{19}}} \right) \cr & \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, = 171. \cr\end{align}
There are 105 questions to complete.