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Ratio
Question 151 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
A box contains 420 coins of 1 rupee, 50 paise and 20 paise coins. The ratio of their values is 13 : 11 : 7. The number of 50 paise coins is =?
132 | |
66 | |
78 | |
42 |
Question 151 Explanation:
| Rs. 1 | : | 50 P | : | 20 P | |
| Values | 13x | : | 11x | : | 7x |
| Number of coins | 13x$\times$1 | : | 11x$\times$2 | : | 7x$\times$5 |
| 13x | : | 22x | : | 35x |
⇒ 13x + 22x + 35x = 420
⇒ 70x = 420 ⇒ x = 6
∴ NUmber of 50 paise coins are = 22x = 22 $\times$ 6 = 132
Question 152 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
Divide Rs. 671 among A, B and C such that if their shares be increased by Rs. 3, Rs. 7 and Rs. 9 respectively the remainder shall be in the ratio 1 : 2 : 3.
Rs. 110, Rs. 220, Rs. 336 | |
Rs. 112, Rs. 223, Rs. 336 | |
Rs. 105, Rs. 223, Rs. 330 | |
None of these |
Question 152 Explanation:
\begin{align} & {\text{Remainder}} \cr & = {\text{Rs}}{\text{.}}\left[ {671 + \left( {3 + 7 + 9} \right)} \right] \cr & = {\text{Rs}}{\text{. }}690. \cr & {\text{A's share}} \cr & = {\text{Rs}}{\text{.}}\left[ {\left( {690 \times \frac{1}{6}} \right) - 3} \right] \cr & = {\text{Rs}}{\text{. }}112. \cr & {\text{B's share}} \cr & = {\text{Rs}}{\text{.}}\left[ {\left( {690 \times \frac{2}{6}} \right) - 7} \right] \cr & = {\text{Rs}}{\text{. }}223. \cr & {\text{C's share}} \cr & = {\text{Rs}}{\text{.}}\left[ {\left( {690 \times \frac{3}{6}} \right) - 9} \right] \cr & = {\text{Rs}}{\text{. }}336. \cr\end{align}
Question 153 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
An amount of money is to be distributed among P, Q ans R in the ratio of 2 : 7 : 9. The total of P's and Q's share is equal to R's share. What is the difference between the shares of P and Q?
Information inadequate | |
Rs. 7500 | |
Rs. 5000 | |
Rs. 9000 |
Question 153 Explanation:
P : Q : R
P + Q = R (given)
2x + 7x = 9x
Hence, we don't have sufficient data to insure the values of A, B and C.
Question 154 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Rs. 38, 000 | |
Rs. 20, 000 | |
Rs. 17, 000 | |
Rs. 25, 500 |
Question 154 Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively. ${\text{Then}}, \, \frac{{2x + 4000}}{{3x + 4000}} = \frac{{40}}{{57}}$ ⇒ 57(2x + 4000) = 40(3x + 4000)
⇒ 6x = 68, 000
⇒ 3x = 34, 000
Sumit's present salary = (3x + 4000) = Rs.(34000 + 4000) = Rs. 38, 000.
Question 155 [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER] |
The numbers x, y, z are proportional to 2, 3, 5. The sum of x, y, z is 100. If y = px - 10, then p is equal to.
5/2 | |
2 | |
3 | |
3/2 |
Question 155 Explanation:
\begin{align} & \to x:y:z = 2:3:5. \cr & \therefore x = \left( {100 \times \frac{2}{{10}}} \right) = 20; \cr & y = \left( {100 \times \frac{3}{{10}}} \right) = 30. \cr & y = px - 10 \cr & \Rightarrow 30 = 20p - 10 \cr & \Rightarrow 20p = 40 \cr & \Rightarrow p = 2. \cr\end{align}
There are 155 questions to complete.